JEE Advanced Mix Test 27

Result

JEE Advanced Mix Test 27

Score
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Rank
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TIME Taken - -

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Weekly Quiz Competition

Question 1
4 / -1

When a galvanometer is shunted with a 4 Ω resistance, the deflection is reduced to one-fifth. If the galvanometer is further shunted with a Ω wire, the further reduction in the deflection will be (the main current remains the same).

A
(8/13) of the deflection when shunted with 4 Ω only

B
(5/14) of the deflection when shunted with 4 Ω only

C
(3/4) of the deflection when shunted with 4 Ω only

D
(3/13) of the deflection when shunted with 4 Ω only

Solution
Question 2
4 / -1

An inductor (x_L = 2 Ω ) a capacitor (xC = 8 Ω ) and a resistance (8 Ω ) is connected in series with an A.C. source. The voltage output of A.C. source is given by v = 10 cos 100πt. The instantaneous potential difference between A and B, when it is half of the voltage output from source at that instant will be :

A
24/7 volts

B
24/5 volts

C
7/24 volts

D
5/24 volts

Solution
Question 3
4 / -1

Figure shows a system of three concentric metal shells A, B and C with radii a, 2a and 3a respectively. Shell B is earthed and shell C is given a charge Q. Now if shell C is connected to shell A, then the final charge on the shell B, is equal to :

A

B

C

D

Solution
Question 4
4 / -1

A ring of mass m, radius r having charge q uniformly distributed over it and free to rotate about its own axis is placed in a region having a magnetic field B parallel to its axis. If the magnetic field is suddenly switched off, the angular velocity acquired by the ring is :

A
qB/m

B
2qB/m

C
qB/2m

D
None of these

Solution
Question 5
4 / -1

Four infinite ladder network containing identical resistances of R Ω each, are combined as shown in figure. The equivalent resistance between A and B is R_AB and between A and C is R_AC. Then the value of is :

A
3/4

B
4/3

C
2

D
1/2

Solution

Let the equivalent resistance of one infinite ladder be x. Then the complete network reduces to
Question 6
4 / -1

Two small balls, each having equal positive charge Q are suspended by two insulating strings of equal length L from a hook fixed to a stand. If the whole set-up is transferred to a satellite in orbit around the earth, the tension in equilibrium in each string is equal to

A
Zero

B

C

D

Solution

A satellite is in a state of free fall & hence weightlessness. Thus only electric force is responsible for the tension
Question 7
4 / -1

In a practical wheat stone bridge circuit as shown, when one more resistance of 100 ? is connected in parallel with unknown resistance ' x ', then ratio l₁/l₂ becomes '2'. l1 is balance length. AB is a uniform wire. Then value of ' x ' must be :

A
50 ?

B
100 ?

C
200 ?

D
400 ?

Solution
Question 8
4 / -1

Loop A of radius (r << R) moves towards loop B with a constant velocity V in such a way that their planes are always parallel. What is the distance between the two loops (x) when the induced emf in loop A is maximum

A
R

B

C
R/2

D

Solution
Question 9
4 / -1

The figure shows, a graph of the current in a discharging circuit of a capacitor through a resistor of resistance 10 Ω.

A
The initial potential difference across the capacitor is 100 volt.

B
The capacitance of the capacitor is F

C
The total heat produced in the circuit will be joules.

D
All are correct

Solution
Question 10
4 / -1

A single circular loop of wire with radius 0.02 m carries a current of 8.0 A. It is placed at the centre of a solenoid that has length 0.65 m, radius 0.080 m and 1300 turns.

A
The value of the current in the solenoid so that the magnetic field at the centre of the loop becomes zero, is equal to 44 mA.

B
The value of the current in the solenoid so that the magnetic field at the centre of the loop becomes zero, is equal to 100 mA.

C
The magnitude of the total magnetic field at the centre of the loop (due to both the loop and the solenoid) if the current in the loop is reversed in direction from that needed to make the total field equal to zero tesla, is 8_p x 10^–5 T.

D
The magnitude of the total magnetic field at the centre of the loop (due to both the loop and the solenoid) if the current in the loop is reversed in direction from that needed to make the total field equal to zero tesla, is 16_p x 10^–5 T.

Solution