JEE Advanced Mix Test 18

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JEE Advanced Mix Test 18

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Weekly Quiz Competition

Question 1
4 / -1

Which of the following has both face-mer and optical isomers ?

A
[Co (NH₃)₃ (NO₃)₃]

B
[Co (ox)₃]^3–

C
[Co (gly)₃]

D
None of these

Solution
Question 2
4 / -1

An inorganic chloride (X) on heating with a sodium hydroxide solution liberates a colourless and non-inflammable gas having characterisitic odour. The salt (X) gives a red colouration with 4-nitrobenzene-diazonium chloride in the presence of sodium hydroxide solution. X is :

A
PH₄Cl

B
NH₄Cl

C
BiCl₃

D
CrO₂Cl₂

Solution
Question 3
4 / -1

A metal nitrate (X) gives a white precipitate with ammonia solution but the precipitate gets dissolved on adding ammonium salts. Lead dioxide and concentrated nitric acid on boiling with a dilute solution of metal nitrate (X) produces a violet-red (or purple) colour solution. Small amount of metal nitrate (X) gives a amethyst-red bead with borax in oxidising flame when cold. The cation of metal nitrate is :

A
Bi³⁺

B
Mg²⁺

C
Zn²⁺

D
Mn²⁺

Solution
Question 4
4 / -1

Which of the following molecules or ions may act as a bidentate ligand ?

A
CO₃^2–

B
NO₃^–

C
CH₃C = N

D
C₂O₄^2–

Solution

CO₃^2- and NO₃^-are flexidentate ligands having 1 or 2 donor oxygen atoms (Source : Shriver Atkins)
C₂O₄^2- – 2 donor oxygen atoms.
CH₃C = N – 1 donor nitrogen atom.
Question 5
4 / -1

Which of the following statements is incorrect ?

A
Ammonium salts on reaction with strong alkalies produce a non-inflamable gas.

B
fac-[Co(NO₃)₃(dien)] is non-chiral.

C
Solid potassium dichromate and concentrated H₂SO₄ liberates chlorine gas with solid sodium chloride.

D
The increasing order of paramagnetic properties amongst VCl₃, VOSO₄, Na₃VO₄, [V(H₂O)₆]SO₄.H₂O is Na₃VO₄ < VOSO₄ < VCl₃ < [V(H₂O)₆] SO₄.H₂O.

Solution
Question 6
4 / -1

Which of the following statements is(are) false ?

A
XeO₃ is a colourless explosive solid and has a pyramidal molecular structure.

B
XeF₂ is not a better oxidising agent.

C
Xe, Kr and Ne all form clatharate compounds.

D
Fluorine in dilute solution of sodium hydroxide disproportionates in fluoride and hypofluorite.

Solution

(B) Statement is false.
2e^- + 2H⁺ + XeF₂ → Xe + 2HF
SRP = +2.64V.
(C) Statement is false as Ne atoms being smaller do not trapp in the cavities formed by water molecules (ice) and
thus does not form clatharte compounds. Xe and Kr being bigger form clathrate compounds.
(D) Statement is false according to the following reaction : 2F₂ + 2NaOH → OF₂(g) + 2NaF + H₂O.
Question 7
4 / -1

Identify the true statement(s).

A
Among the oxides MnO, Mn₂O₃, MnO₂ and Mn₂O₇, the last one is most acidic.

B
H¯ is a powerful reductant and a very strong base.

C
In the molecule FNO₃, two oxygen atoms are in –1 oxidation state each.

D
There are four P–P bonds in the P₄ molecule.

Solution

(A) As oxidation state of Mn increases, the difference in values of electronegativities of Mn and O decrease and thus
acidic character increase. In Mn₂O₇, the Mn is in highest oxidation state + 7. So, it is most acidic.
(B) It is factual.
Question 8
4 / -1

Statement-1 : Argon is used in the laboratory for handling substances that are air-sensitive.

Statement-2 : Argon is inert towards chemical reactivity due to the completely filled valence shell electronic configuration, high ionization enthalpy and more positive electron gain enthalpy.

A
Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.

B
Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1.

C
Statement-1 is True, Statement-2 is False.

D
Statement-1 is False, Statement-2 is True.

Solution

S1 and S2 both are correct statement and S2 is the correct explanation of S1 .
Question 9
4 / -1

Statement-1: tris(ethane-1, 2-diamine)nickel(II) nitrate is homoleptic outer orbital complex and paramagnetic with two unpaired electrons.

Statement-2: Complex tris(ethane-1, 2-diamine)nickel(II) nitrate when treated with a neutral solution of a thiosulphate produces a crystalline, green precipitate.

A
Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.

B
Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1.

C
Statement-1 is True, Statement-2 is False.

D
Statement-1 is False, Statement-2 is True.

Solution

Statement-1 : [Ni (en)₃] (NO₃)₂ is paramagnetic with two unpaired electrons and has octahedral geometry with sp³d²
hybridisation and as nd orbital participate in hybridisation it is outer orbital complex. As all ligands are of same type,
the complex is termed as homoleptic.
Question 10
4 / -1

What is (Z) ?

A
It is a salt of Fe³⁺

B
It is a salt of Sn⁴⁺

C
It is a salt of Mn²⁺

D
It is a salt of Cr⁶⁺

Solution

This reaction is Vohhard method for estimation of manganese carried out in presence of ZnSO₄ or suspended ZnO which catalyses the oxidation.

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JEE Advanced Mix Test 18

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JEE Advanced Mix Test 18

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Question 1

[Co (NH3)3 (NO3)3]

[Co (ox)3]3–

[Co (gly)3]

None of these

Solution

Question 2

PH4Cl

NH4Cl

BiCl3

CrO2Cl2

Solution

Question 3

Bi3+

Mg2+

Zn2+

Mn2+

Solution

Question 4

CO32–

NO3–

CH3C = N

C2O42–

Solution

Question 5

Ammonium salts on reaction with strong alkalies produce a non-inflamable gas.

fac-[Co(NO3)3(dien)] is non-chiral.

Solid potassium dichromate and concentrated H2SO4 liberates chlorine gas with solid sodium chloride.

The increasing order of paramagnetic properties amongst VCl3, VOSO4, Na3VO4, [V(H2O)6]SO4.H2O is Na3VO4 < VOSO4 < VCl3 < [V(H2O)6] SO4.H2O.

Solution

Question 6

XeO3 is a colourless explosive solid and has a pyramidal molecular structure.

XeF2 is not a better oxidising agent.

Xe, Kr and Ne all form clatharate compounds.

Fluorine in dilute solution of sodium hydroxide disproportionates in fluoride and hypofluorite.

Solution

Question 7

Among the oxides MnO, Mn2O3, MnO2 and Mn2O7, the last one is most acidic.

H¯ is a powerful reductant and a very strong base.

In the molecule FNO3, two oxygen atoms are in –1 oxidation state each.

There are four P–P bonds in the P4 molecule.

Solution

Question 8

Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.

Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1.

Statement-1 is True, Statement-2 is False.

Statement-1 is False, Statement-2 is True.

Solution

Question 9

Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.

Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1.

Statement-1 is True, Statement-2 is False.

Statement-1 is False, Statement-2 is True.

Solution

Question 10

It is a salt of Fe3+

It is a salt of Sn4+

It is a salt of Mn2+

It is a salt of Cr6+

Solution

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[Co (NH₃)₃ (NO₃)₃]

[Co (ox)₃]^3–

[Co (gly)₃]

PH₄Cl

NH₄Cl

BiCl₃

CrO₂Cl₂

Bi³⁺

Mg²⁺

Zn²⁺

Mn²⁺

CO₃^2–

NO₃^–

CH₃C = N

C₂O₄^2–

fac-[Co(NO₃)₃(dien)] is non-chiral.

Solid potassium dichromate and concentrated H₂SO₄ liberates chlorine gas with solid sodium chloride.

The increasing order of paramagnetic properties amongst VCl₃, VOSO₄, Na₃VO₄, [V(H₂O)₆]SO₄.H₂O is Na₃VO₄ < VOSO₄ < VCl₃ < [V(H₂O)₆] SO₄.H₂O.

XeO₃ is a colourless explosive solid and has a pyramidal molecular structure.

XeF₂ is not a better oxidising agent.

Among the oxides MnO, Mn₂O₃, MnO₂ and Mn₂O₇, the last one is most acidic.

In the molecule FNO₃, two oxygen atoms are in –1 oxidation state each.

There are four P–P bonds in the P₄ molecule.

It is a salt of Fe³⁺

It is a salt of Sn⁴⁺

It is a salt of Mn²⁺

It is a salt of Cr⁶⁺